2[t+2(2t+3)]=11

Solution for 2[t+2(2t+3)]=11 equation:

Simplifying
2[t + 2(2t + 3)] = 11

Reorder the terms:
2[t + 2(3 + 2t)] = 11
2[t + (3 * 2 + 2t * 2)] = 11
2[t + (6 + 4t)] = 11

Reorder the terms:
2[6 + t + 4t] = 11

Combine like terms: t + 4t = 5t
2[6 + 5t] = 11
[6 * 2 + 5t * 2] = 11
[12 + 10t] = 11

Solving
12 + 10t = 11

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 10t = 11 + -12

Combine like terms: 12 + -12 = 0
0 + 10t = 11 + -12
10t = 11 + -12

Combine like terms: 11 + -12 = -1
10t = -1

Divide each side by '10'.
t = -0.1

Simplifying
t = -0.1